Tiled Room
Two walls, a checkerboard floor, and a picture frame. Just needs a tiny couch (⌐■_■)
| Grid | Code Size | Leaderboard | Cycles | Leaderboard | Date |
|---|---|---|---|---|---|
| 13x13x13 | 53 | #97 | 10.774 | #1365 | 2026-02-23 |
Solution
p=x*x|y*y return y==-6 and x+z<<1&2|12 or(z==6 or x==-6)and(p<9 and x*y~=0 and 0 or p<16 and 15 or 1)How it works
Three surfaces crammed into one return statement!
The floor (y==-6) uses a fun bit trick: x+z<<1&2|12 shifts the parity bit of x+z into position, masks it, then ORs with 12. The result alternates between 12 (darkblue) and 14 (lightblue) without a single and/or branch.
The walls (z==6 back wall, x==-6 left wall) have a brown picture frame with empty windows. We stash x*x|y*y in p so we can cheaply check whether we’re inside different distance thresholds. p<9 catches the inner region (where abs(x)<3 and abs(y)<3), p<16 catches the frame border. The x*y~=0 check carves out the holes by keeping only voxels where neither coordinate is zero, returning 0 (empty) for those.
The x*x|y*y trick is the star here. Bitwise OR of two squares acts like a “both coordinates in range” check: if either square is too big, the OR result blows past the threshold. Way cheaper than two separate abs() comparisons!